If z=2-3i, show that z2-4z+13=0, hence find the value of 4z3-3z2+169.

If $z = 2 - 3 i$ , show that $z^{2} - 4 z + 13 = 0$ , hence find the value of $4 z^{3} - 3 z^{2} + 169 .$

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